The complex numbers sin x + i cos 2x and cos | vedclass

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(D) Two complex numbers $z_1 = a + ib$ and $z_2 = c + id$ are conjugate to each other if $z_1 = \overline{z_2}$.Given $z_1 = \sin x + i \cos 2x$ and $

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No value of $x$

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(D) Two complex numbers $z_1 = a + ib$ and $z_2 = c + id$ are conjugate to each other if $z_1 = \overline{z_2}$.Given $z_1 = \sin x + i \cos 2x$ and $z_2 = \cos x - i \sin 2x$.The conjugate of $z_2$ is $\overline{z_2} = \cos x + i \sin 2x$.For $z_1 = \overline{z_2}$,we must have $\sin x + i \cos 2x = \cos x + i \sin 2x$.Equating real and imaginary parts:$1$) $\sin x = \cos x \implies 	an x = 1 \implies x = n\pi + \frac{\pi}{4}$.$2$) $\cos 2x = \sin 2x \implies 	an 2x = 1 \implies 2x = m\pi + \frac{\pi}{4} \implies x = \frac{m\pi}{2} + \frac{\pi}{8}$.Comparing the two conditions for $x$,there is no common value of $x$ that satisfies both equations simultaneously.Therefore,there is no value of $x$ for which the given complex numbers are conjugates.

The complex numbers $\sin x + i \cos 2x$ and $\cos x - i \sin 2x$ (where $i = \sqrt{-1}$) are conjugate to each other for:

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