The compound in which C^* uses sp^3 hybrid or | vedclass

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(C) In the compound $CH_3-CH_2-OH$,the carbon atom marked $C^*$ (the one attached to the hydroxyl group) is bonded to four other atoms (three hydrogen

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$CH_3-CH_2-OH$

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(C) In the compound $CH_3-CH_2-OH$,the carbon atom marked $C^*$ (the one attached to the hydroxyl group) is bonded to four other atoms (three hydrogens and one oxygen) via single bonds. Since it forms four sigma bonds and has no lone pairs,its steric number is $4$,which corresponds to $sp^3$ hybridization. In $H-COOH$,$(NH_2)_2-C=O$,and $CH_3-CHO$,the carbon atom $C^*$ is involved in a double bond with oxygen,making it $sp^2$ hybridized.

The compound in which $C^*$ uses $sp^3$ hybrid orbitals for bond formation is

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