The hybridization of C_2 and C_3 in CH_3-CH=C | vedclass

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(B) The structure of the given molecule is $CH_3-CH=C=CH-CH_3$.To determine the hybridization, we count the number of sigma bonds and lone pairs aroun

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$sp^2, sp$

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(B) The structure of the given molecule is $CH_3-CH=C=CH-CH_3$.To determine the hybridization, we count the number of sigma bonds and lone pairs around the carbon atom.For $C_2$: It is bonded to one $H$ atom, one $CH_3$ group (single bond), and one $C_3$ atom (double bond). It has $3$ sigma bonds and $0$ lone pairs, so it is $sp^2$ hybridized.For $C_3$: It is bonded to $C_2$ (double bond) and $C_4$ (double bond). It has $2$ sigma bonds and $0$ lone pairs, so it is $sp$ hybridized.Therefore, the hybridization of $C_2$ and $C_3$ is $sp^2$ and $sp$ respectively.

The hybridization of $C_2$ and $C_3$ in $CH_3-CH=C=CH-CH_3$ is

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