The compound interest on a certain sum for 2 | vedclass

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(B) Let the principal sum be $P$.Given compound interest ($C$.$I$.) for $n = 2$ years at $r = 10 \%$ per annum is ₹ $525$.Formula for $C$.$I$. $= P \l

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$500$

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(B) Let the principal sum be $P$.Given compound interest ($C$.$I$.) for $n = 2$ years at $r = 10 \%$ per annum is ₹ $525$.Formula for $C$.$I$. $= P \left[ \left( 1 + \frac{r}{100} ight)^n - 1 ight] = 525$.$P \left[ \left( 1 + \frac{10}{100} ight)^2 - 1 ight] = 525$$P \left[ (1.1)^2 - 1 ight] = 525$$P [1.21 - 1] = 525$$P (0.21) = 525$$P = \frac{525}{0.21} = \frac{52500}{21} = ₹ 2500$.Now,we need to find simple interest ($S$.$I$.) for double the time ($n' = 2 	imes 2 = 4$ years) at half the rate ($r' = \frac{10}{2} = 5 \%$ per annum).$S$.$I$. $= \frac{P 	imes r' 	imes n'}{100} = \frac{2500 	imes 5 	imes 4}{100} = 25 	imes 20 = ₹ 500$.

The compound interest on a certain sum for $2$ years at $10 \%$ per annum is ₹ $525$. The simple interest (in ₹) on the same sum for double the time at half the rate per cent per annum is

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