The compressibility of water is 6 times 10^{- | vedclass

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(B) The compressibility $K$ is defined as the reciprocal of the bulk modulus $\beta$,given by $K = \frac{1}{\beta} = -\frac{1}{V} \frac{\Delta V}{\Del

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$24$

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(B) The compressibility $K$ is defined as the reciprocal of the bulk modulus $\beta$,given by $K = \frac{1}{\beta} = -\frac{1}{V} \frac{\Delta V}{\Delta P}$.Rearranging the formula to find the change in volume $\Delta V$,we get: $-\Delta V = K \cdot V \cdot P$.Given values:Compressibility $K = 6 	imes 10^{-10} \ N^{-1} \ m^2$.Initial volume $V = 1 \ litre = 1000 \ cc = 10^{-3} \ m^3$.Pressure $P = 4 	imes 10^7 \ N \ m^{-2}$.Substituting these values into the equation:$-\Delta V = (6 	imes 10^{-10}) 	imes (10^{-3}) 	imes (4 	imes 10^7)$.$-\Delta V = 24 	imes 10^{-6} \ m^3$.Since $1 \ m^3 = 10^6 \ cc$,we have:$-\Delta V = 24 	imes 10^{-6} 	imes 10^6 \ cc = 24 \ cc$.

The compressibility of water is $6 \times 10^{-10} \ N^{-1} \ m^2$. If one litre is subjected to a pressure of $4 \times 10^7 \ N \ m^{-2}$,the decrease in its volume is (in $cc$):

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