The conductivity of a $0.05 \, M$ solution of a weak monobasic acid is $10^{-3} \, S \, cm^{-1}$. If $\lambda_{m}^{\infty}$ for the weak acid is $500 \, S \, cm^{2} \, mol^{-1}$,calculate the $K_{a}$ of the weak monobasic acid.

  • A
    $8 \times 10^{-5}$
  • B
    $4 \times 10^{-6}$
  • C
    $16 \times 10^{-7}$
  • D
    $14 \times 10^{-8}$

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