The converse of the statement $((\sim p) \wedge q) \Rightarrow r$ is

The negation of the statement pattern $\sim s \vee (\sim r \wedge s)$ is equivalent to

The negation of $(p$ $\Rightarrow q)$ $\Rightarrow (q$ $\Rightarrow p)$ is

Write the following statement in the form of "if-then":
To get an $A^{+}$ in the class,it is necessary that you do all the exercises of the book.

The dual of the converse of the inverse of the logical statement $p \to (q \to r)$ is equivalent to...

Which of the following statement$(s)$ is/are not true?
$I$) If $1$ is not a prime number, then $2$ is not a prime number.
$II$) $e$ is a vowel and $12 \times 3 = 36$.
$III$) It is not true that $14$ is a composite number and $3$ is an even number.
$IV$) $\sqrt{5}$ is an irrational number, but $3 + \sqrt{5}$ is a complex number.