The correct order for the wavelength of absor | vedclass

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(A) The energy of absorption $(E)$ is inversely proportional to the wavelength of absorption $(\lambda)$,i.e.,$E = \frac{hc}{\lambda}$.According to th

Vedclass · Accepted Answer

$[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$

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(A) The energy of absorption $(E)$ is inversely proportional to the wavelength of absorption $(\lambda)$,i.e.,$E = \frac{hc}{\lambda}$.According to the spectrochemical series,the field strength of the ligands follows the order: $H_2O Stronger field ligands cause a larger crystal field splitting energy $(\Delta_o)$,which corresponds to higher energy absorption and thus a shorter wavelength of absorption.Therefore,the order of field strength is $[Ni(H_2O)_6]^{2+} Consequently,the order of wavelength of absorption is the inverse: $[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$.

The correct order for the wavelength of absorption in the visible region is

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