The correct order of 2^{nd} ionisation potent | vedclass

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Question

(C) The $2^{nd}$ ionisation potential corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.The electronic configura

Vedclass · Accepted Answer

$O > F > N > C$

Vedclass · Answer

(C) The $2^{nd}$ ionisation potential corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.The electronic configurations of the unipositive ions are:$C^+ (1s^2 2s^2 2p^1)$$N^+ (1s^2 2s^2 2p^2)$$O^+ (1s^2 2s^2 2p^3)$$F^+ (1s^2 2s^2 2p^4)$$O^+$ has a stable half-filled $2p^3$ configuration,which makes it very difficult to remove the second electron,resulting in the highest $2^{nd}$ ionisation potential.Comparing the others,$F^+$ has a higher effective nuclear charge than $N^+$,and $N^+$ has a higher effective nuclear charge than $C^+$.Thus,the correct order is $O > F > N > C$.

Element	Ionization enthalpy $(kJ \ mol^{-1})$ $(1^{st}, 2^{nd}, 3^{rd})$
$A$	$899, 1757, 14847$
$B$	$737, 1450, 7731$

The correct order of $2^{nd}$ ionisation potential of carbon,nitrogen,oxygen and fluorine is

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Consider the following ionization enthalpies of two elements $A$ and $B$.

Element Ionization enthalpy $(kJ \ mol^{-1})$ $(1^{st}, 2^{nd}, 3^{rd})$

$A$ $899, 1757, 14847$

$B$ $737, 1450, 7731$

Which of the following statements is correct?

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