The correct order of increasing s- character | vedclass

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(A) To determine the $s-$ character,we calculate the hybridization of the central atom in each species:$I. CO_3^{2-}$: The central $C$ atom is $sp^2$

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$II < III < IV < I < V$

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(A) To determine the $s-$ character,we calculate the hybridization of the central atom in each species:$I. CO_3^{2-}$: The central $C$ atom is $sp^2$ hybridized. $s-$ character $= (1/3) 	imes 100 \approx 33.3\%$.$II. XeF_4$: The central $Xe$ atom is $sp^3d^2$ hybridized. $s-$ character $= (1/6) 	imes 100 \approx 16.6\%$.$III. I_3^{-}$: The central $I$ atom is $sp^3d$ hybridized. $s-$ character $= (1/5) 	imes 100 = 20\%$.$IV. NCl_3$: The central $N$ atom is $sp^3$ hybridized. $s-$ character $= (1/4) 	imes 100 = 25\%$.$V. BeCl_2$: The central $Be$ atom is $sp$ hybridized. $s-$ character $= (1/2) 	imes 100 = 50\%$.Comparing the percentages: $16.6\% (II) Thus,the correct order is $II < III < IV < I < V$.

The correct order of increasing $s-$ character (in percentage) in the hybrid orbitals of the following molecules/ions is:
$I. CO_3^{2-}$
$II. XeF_4$
$III. I_3^{-}$
$IV. NCl_3$
$V. BeCl_2$

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The correct order of increasing $s-$ character (in percentage) in the hybrid orbitals of the following molecules/ions is:$I. CO_3^{2-}$$II. XeF_4$$III. I_3^{-}$$IV. NCl_3$$V. BeCl_2$