The correct order of increasing s-character ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The hybridizations and corresponding $s-$character percentages are as follows:$I. CO_3^{2-}: sp^2$ hybridization,$s-$character $= \frac{1}{3} 	im

Vedclass · Accepted Answer

$II < III < IV < I < V$

Vedclass · Answer

(A) The hybridizations and corresponding $s-$character percentages are as follows:$I. CO_3^{2-}: sp^2$ hybridization,$s-$character $= \frac{1}{3} 	imes 100 \approx 33.3\%$$II. XeF_4: sp^3d^2$ hybridization,$s-$character $= \frac{1}{6} 	imes 100 \approx 16.6\%$$III. I_3^-: sp^3d$ hybridization,$s-$character $= \frac{1}{5} 	imes 100 = 20\%$$IV. NCl_3: sp^3$ hybridization,$s-$character $= \frac{1}{4} 	imes 100 = 25\%$$V. BeCl_2: sp$ hybridization,$s-$character $= \frac{1}{2} 	imes 100 = 50\%$Comparing the percentages: $16.6\% (II) Therefore,the correct increasing order is $II < III < IV < I < V$.

The correct order of increasing $s-$character (in percentage) in the hybrid orbitals of the following molecules/ions is:
$(I)$ $CO_3^{2-}$ $(II)$ $XeF_4$ $(III)$ $I_3^-$ $(IV)$ $NCl_3$ $(V)$ $BeCl_2$

Similar Questions

Let $P$ be a plane passing through the points $(2,1,0)$,$(4,1,1)$ and $(5,0,1)$ and $R$ be the point $(2,1,6)$. Then the image of $R$ in the plane $P$ is

$A$ chloro compound of vanadium has a spin-only magnetic moment of $1.73 \ BM$. This vanadium chloride has the formula: (Atomic number of $V = 23$)

$\sqrt{2+\sqrt{5}-\sqrt{6-3 \sqrt{5}+\sqrt{14-6 \sqrt{5}}}}$ is equal to

$A$ bucket tied at the end of a $1.6\, m$ long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill,when the bucket is at the highest position? (Take $g = 10\, m/sec^2$)

What is $Endosulfan$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of increasing $s-$character (in percentage) in the hybrid orbitals of the following molecules/ions is:$(I)$ $CO_3^{2-}$ $(II)$ $XeF_4$ $(III)$ $I_3^-$ $(IV)$ $NCl_3$ $(V)$ $BeCl_2$