The correct order of ionic radii of $Ce, La, Pm$ and $Yb$ in $+3$ oxidation state is:
- A$La^{3+} < Pm^{3+} < Ce^{3+} < Yb^{3+}$
- B$La^{3+} < Ce^{3+} < Pm^{3+} < Yb^{3+}$
- C$Yb^{3+} < Ce^{3+} < Pm^{3+} < La^{3+}$
- D$Yb^{3+} < Pm^{3+} < Ce^{3+} < La^{3+}$
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View SolutionThe electronic configurations of bivalent europium and trivalent cerium are
(atomic number : $Xe=54, Ce=58, Eu=63$ )
(atomic number : $Xe=54, Ce=58, Eu=63$ )
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