The electronic configurations of bivalent europium and trivalent cerium are
(atomic number : $Xe=54, Ce=58, Eu=63$ )

  • A
    $[Xe] 4f^{4}$ and $[Xe] 4f^{9}$
  • B
    $[Xe] 4f^{7}$ and $[Xe] 4f^{1}$
  • C
    $[Xe] 4f^{7} 6s^{2}$ and $[Xe] 4f^{2} 6s^{2}$
  • D
    $[Xe] 4f^{2}$ and $[Xe] 4f^{7}$

Explore More

Similar Questions

Explain the lanthanoid contraction.

Which among the following lanthanoids forms the most stable $+2$ oxidation state?

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: $5f$ electrons can participate in bonding to a far greater extent than $4f$ electrons.
Reason $R$: $5f$ orbitals are not as buried as $4f$ orbitals.
In the light of the above statements,choose the correct answer from the options given below:

Which one amongst the following are good oxidizing agents?
$A.$ $Sm^{2+}$
$B.$ $Ce^{2+}$
$C.$ $Ce^{4+}$
$D.$ $Tb^{4+}$
Choose the most appropriate answer from the options given below:

What is the electronic configuration of $Ce$ $(Z = 58)$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo