The correct order of ionic size of $N^{3-}$,$Na^{+}$,$F^{-}$,$Mg^{2+}$,and $O^{2-}$ is:

  • A
    $Mg^{2+} > Na^{+} > F^{-} > O^{2-} > N^{3-}$
  • B
    $N^{3-} < F^{-} < O^{2-} < Na^{+} < Mg^{2+}$
  • C
    $Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$
  • D
    $N^{3-} > O^{2-} > F^{-} > Na^{+} > Mg^{2+}$

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On going down a main sub-group in the periodic table (example $Li$ to $Cs$ in $IA$ or $Be$ to $Ra$ in $IIA$),the expected trend of changes in atomic radius is a

Increasing order of ionic size for the ions,$F^{-}$,$O^{2-}$,$Na^{+}$,$Al^{3+}$ is :-

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Explain why cations are smaller and anions larger in radii than their parent atoms.

Which of the following is the incorrect order of ionic/atomic radius?

Assertion $(A)$: $Mg^{2+}$ and $Al^{3+}$ are isoelectronic but the magnitude of the ionic radius of $Al^{3+}$ is less than that of $Mg^{2+}$.
Reason $(R)$: The effective nuclear charge on the outermost electrons in $Al^{3+}$ is greater than that in $Mg^{2+}$.
The correct option among the following is:

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