The correct order of reducing ability of the following hydrides is:

  • A
    $BiH_3 > SbH_3 > PH_3 > NH_3$
  • B
    $NH_3 > PH_3 > SbH_3 > BiH_3$
  • C
    $SbH_3 > BiH_3 > PH_3 > NH_3$
  • D
    $PH_3 > BiH_3 > SbH_3 > NH_3$

Explore More

Similar Questions

In case of nitrogen,$NCl_3$ is possible but not $NCl_5$,while in case of phosphorus,$PCl_3$ as well as $PCl_5$ are possible. This is due to:

In which of the following options are the product gases $X$ and $Y$ (other than water vapour) the same?

Correct statements from the following are: $A$. Nitrogen in oxidation states from $+1$ to $+4$ disproportionates in acid medium. $B$. Nitrogen has the ability to form $d\text{--}p$ multiple bonds with itself and other elements with small size and high electronegativity. $C$. $N$-$N$ single bond is stronger than $P$-$P$ single bond. $D$. Nitrogen has highest density in its group due to small size. $E$. The maximum covalency of nitrogen is four since it has only four valence orbitals for bonding.

The structure of white phosphorus is ........ .

Which of the following gases is diamagnetic and neutral towards water?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo