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(D) Step $1$: Calculate the number of atoms in $2$ moles of cyclohexane $(C_6H_{12})$.One molecule of cyclohexane contains $6 + 12 = 18$ atoms.Total a

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$B > A > C$

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(D) Step $1$: Calculate the number of atoms in $2$ moles of cyclohexane $(C_6H_{12})$.One molecule of cyclohexane contains $6 + 12 = 18$ atoms.Total atoms $= 2 	ext{ mol} 	imes 18 	imes N_A = 36 N_A$.Step $2$: Calculate the number of atoms in $684 	ext{ g}$ of sucrose $(C_{12}H_{22}O_{11})$.Molar mass of sucrose $= (12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 144 + 22 + 176 = 342 	ext{ g/mol}$.Moles of sucrose $= 684 	ext{ g} / 342 	ext{ g/mol} = 2 	ext{ mol}$.One molecule of sucrose contains $12 + 22 + 11 = 45$ atoms.Total atoms $= 2 	ext{ mol} 	imes 45 	imes N_A = 90 N_A$.Step $3$: Calculate the number of atoms in $90.8 	ext{ L}$ of dihydrogen $(H_2)$ at $STP$.Moles of $H_2 = 90.8 	ext{ L} / 22.7 	ext{ L/mol} \approx 4 	ext{ mol}$ (using standard molar volume $22.7 	ext{ L/mol}$ at $1 	ext{ bar}$ $STP$).One molecule of $H_2$ contains $2$ atoms.Total atoms $= 4 	ext{ mol} 	imes 2 	imes N_A = 8 N_A$.Comparing the values: $B (90 N_A) > A (36 N_A) > C (8 N_A)$.Thus, the correct order is $B > A > C$.

Column - $A$	Column - $B$
$(A)$ $88 \ g$ of $CO_2$	$(1)$ $0.2 \ mol$
$(B)$ $6.022 \times 10^{23}$ molecules of water	$(2)$ $2 \ mol$
$(C)$ $5.6 \ L$ of $O_2$ at $STP$	$(3)$ $1 \ mol$
$(D)$ $96 \ g$ of $O_2$	$(4)$ $6.022 \times 10^{23}$ molecules
$(E)$ One mole of any gas at $STP$	$(5)$ $3 \ mol$

The correct order of the total number of atoms present in
$(A)$ $2$ moles of cyclohexane
$(B)$ $684 \text{ g}$ of sucrose
$(C)$ $90.8 \text{ L}$ of dihydrogen at $STP$
is:

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The correct order of the total number of atoms present in $(A)$ $2$ moles of cyclohexane $(B)$ $684 \text{ g}$ of sucrose $(C)$ $90.8 \text{ L}$ of dihydrogen at $STP$ is: