The correct sequence of bond order is

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(D) The bond order is calculated using the Molecular Orbital Theory $(MOT)$ formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For $O_2^+ (15 \ e^-)$:

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$O_2^+ > O_2 > O_2^-$

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(D) The bond order is calculated using the Molecular Orbital Theory $(MOT)$ formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For $O_2^+ (15 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$. Bond order = $\frac{10 - 5}{2} = 2.5$.For $O_2 (16 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. Bond order = $\frac{10 - 6}{2} = 2.0$.For $O_2^- (17 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$. Bond order = $\frac{10 - 7}{2} = 1.5$.Thus,the correct sequence is $O_2^+ > O_2 > O_2^-$.

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Given below are two statements:
Statement $(I)$: The correct sequence of bond lengths in the following species is:
$O_2^+ < O_2 < O_2^- < O_2^{2-}$
Statement $(II)$: The correct sequence of number of unpaired electrons in the following species is:
$O_2 > O_2^+ > O_2^- > O_2^{2-}$

The decreasing order of stability of $O_2, O_{2}^{-}, O_{2}^{+}$ and $O_2^{2-}$ is:

The changes in bond length with respect to $N-N$ and $O-O$,when $N_2$ becomes $N_2^{+}$ and $O_2$ becomes $O_2^{+}$ are respectively

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