The correct set of quantum numbers for the un | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$.There is only one unpaired electron,which is located in the $4s$ orbital.For

Vedclass · Accepted Answer

$n=4, l=0, m=0, s=+\frac{1}{2}$

Vedclass · Answer

(C) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$.There is only one unpaired electron,which is located in the $4s$ orbital.For the $4s$ orbital,the principal quantum number $n=4$.The azimuthal quantum number $l=0$ for an $s$-orbital.The magnetic quantum number $m=0$.The spin quantum number $s$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$.Thus,the correct set of quantum numbers is $n=4, l=0, m=0, s=+\frac{1}{2}$.

The correct set of quantum numbers for the unpaired electron of $Cu$ atom is

Similar Questions

Consider the Argon atom. For how many electrons does this atom have $m = 1$?

The number of waves made by an electron moving in an orbit having a maximum magnetic quantum number $(m_l) = 3$ is:

According to which principle is the electronic configuration of nitrogen $1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1$ and not $1s^2 2s^2 2p_x^2 2p_y^1 2p_z^0$?

In the following pairs,which orbital experiences greater nuclear attraction?
$(i)$ $4f$ and $5d$ $(ii)$ $4d$ and $5s$ $(iii)$ $7s$ and $5f$ $(iv)$ $7p$ and $5p$
$(v)$ $3d$ and $3f$

For $3d_{z^2}$ calculate the value of $n, \ell, m$ and $s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module