The correct structure of product A formed in | vedclass

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Question

(A) The given reaction is a Cannizzaro reaction involving benzaldehyde $(PhCHO)$ in the presence of a base $(NaOD)$ and a deuterated solvent $(D_2O)$.

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(A) The given reaction is a Cannizzaro reaction involving benzaldehyde $(PhCHO)$ in the presence of a base $(NaOD)$ and a deuterated solvent $(D_2O)$.In the mechanism of the Cannizzaro reaction, the hydride ion $(H^-)$ is transferred from the tetrahedral intermediate of one aldehyde molecule to the carbonyl carbon of another aldehyde molecule.Since the reaction is carried out in $D_2O$, the oxygen atom of the hydroxyl group in the resulting alcohol will exchange its hydrogen with deuterium, leading to the formation of an $-OD$ group.However, the hydrogen atom attached to the alpha-carbon of the alcohol $(PhCH_2OD)$ comes from the aldehyde carbon $(PhCHO)$, which does not exchange with the solvent during the hydride transfer step.Therefore, the product formed is benzyl alcohol with a deuterated hydroxyl group, which is $Ph-CH_2-OD$.

List-$I$	List-$II$
$A$. Grignard reagent	$1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction	$2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction	$3$. $CH_3MgX$
$D$. Wolff-Kishner reduction	$4$. $Zn-Hg / \text{conc. } HCl$
	$5$. $H_2 / Ni$

The correct structure of product $A$ formed in the following reaction:
$PhCHO + PhCHO \xrightarrow[in\, D_2O]{NaOD} A + PhCOO^{-}$
($Ph$ is $-C_6H_5$)

Similar Questions

The major products of the following reaction are:

$CH_3-CH=CH-CH_2OH \xrightarrow{PCC} CH_3-CH=CH-CHO$
What is the change in hybridisation at $C-1$ in the above reaction?

Fehling solution is

Match the following lists:
List-$I$ List-$II$
$A$. Grignard reagent $1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction $2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction $3$. $CH_3MgX$
$D$. Wolff-Kishner reduction $4$. $Zn-Hg / \text{conc. } HCl$
$5$. $H_2 / Ni$

What are the correct products of the following reaction?
$CH_3CH_2COCH_3 \xrightarrow{NaOCl} \text{Products}$

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The correct structure of product $A$ formed in the following reaction:$PhCHO + PhCHO \xrightarrow[in\, D_2O]{NaOD} A + PhCOO^{-}$($Ph$ is $-C_6H_5$)