(A) Length of the fence (in $m$) $= \frac{\text{Total cost}}{\text{Rate}} = \frac{5280}{24} = 220$.So,the circumference of the field $= 220\, m$.Let $

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(A) Length of the fence (in $m$) $= \frac{\text{Total cost}}{\text{Rate}} = \frac{5280}{24} = 220$.So,the circumference of the field $= 220\, m$.Let $r$ be the radius of the field. Then,$2\pi r = 220$.$2 \times \frac{22}{7} \times r = 220$.$r = \frac{220 \times 7}{2 \times 22} = 35\, m$.Area of the field $= \pi r^2 = \frac{22}{7} \times 35 \times 35 = 22 \times 5 \times 35 = 3850\, m^2$.Cost of ploughing $1\, m^2$ of the field $= Rs. 0.50$.Total cost of ploughing the field $= 3850 \times 0.50 = Rs. 1925$.

Class 10 Mathematics Areas Related to Circles Textbook - Areas Related to Circles

Medium

The cost of fencing a circular field at the rate of $Rs. 24$ per metre is $Rs. 5280$. The field is to be ploughed at the rate of $Rs. 0.50$ per $m^2$. Find the cost of ploughing the field (Take $\pi = \frac{22}{7}$). (in $Rs.$)

A
$1925$
B
$220$
C
$1800$
D
$1850$

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Areas Related to Circles

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Textbook - Areas Related to Circles

Find the area of the shaded region in the figure if $ABCD$ is a square of side $14 \, cm$ and $APD$ and $BPC$ are semicircles. (in $cm^2$) [Use $\pi = \frac{22}{7}$]

Medium

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Find the area of the shaded design in the figure where $ABCD$ is a square of side $10 \, cm$ and semicircles are drawn with each side of the square as diameter. (in $cm^2$) (Use $\pi = 3.14$)

Difficult

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In a circular table cover of radius $32 \, cm$,a design is formed by leaving an equilateral triangle $ABC$ in the middle as shown in the figure. Find the area of the design. [Use $\pi = \frac{22}{7}$]

Medium

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In the figure,a square $OABC$ is inscribed in a quadrant $OPBQ$. If $OA = 20 \, cm,$ find the area of the shaded region. (in $cm^2$) (Use $\pi = 3.14$)

Medium

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Find the area of the sector of a circle with radius $4\, cm$ and of angle $30^{\circ}$. Also,find the area of the corresponding major sector (in $cm^2$) (Use $\pi = 3.14$).

Medium

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The cost of fencing a circular field at the rate of $Rs. 24$ per metre is $Rs. 5280$. The field is to be ploughed at the rate of $Rs. 0.50$ per $m^2$. Find the cost of ploughing the field (Take $\pi = \frac{22}{7}$). (in $Rs.$)

Similar Questions

Find the area of the shaded region in the figure if $ABCD$ is a square of side $14 \, cm$ and $APD$ and $BPC$ are semicircles. (in $cm^2$) [Use $\pi = \frac{22}{7}$]

Find the area of the shaded design in the figure where $ABCD$ is a square of side $10 \, cm$ and semicircles are drawn with each side of the square as diameter. (in $cm^2$) (Use $\pi = 3.14$)

In a circular table cover of radius $32 \, cm$,a design is formed by leaving an equilateral triangle $ABC$ in the middle as shown in the figure. Find the area of the design. [Use $\pi = \frac{22}{7}$]

In the figure,a square $OABC$ is inscribed in a quadrant $OPBQ$. If $OA = 20 \, cm,$ find the area of the shaded region. (in $cm^2$) (Use $\pi = 3.14$)

Find the area of the sector of a circle with radius $4\, cm$ and of angle $30^{\circ}$. Also,find the area of the corresponding major sector (in $cm^2$) (Use $\pi = 3.14$).

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