The crystal field splitting energy of [Co(oxa | vedclass

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(B) The crystal field splitting energy $(\Delta_0)$ for an octahedral complex depends on the oxidation state of the metal ion and the nature of the li

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$2$

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(B) The crystal field splitting energy $(\Delta_0)$ for an octahedral complex depends on the oxidation state of the metal ion and the nature of the ligand.For $[Co(oxalate)_3]^{3-}$, the metal is $Co^{3+}$ ($3d^6$ configuration).For $[Cr(oxalate)_3]^{3-}$, the metal is $Cr^{3+}$ ($3d^3$ configuration).Generally, $\Delta_0$ increases with the oxidation state of the metal ion. For the same ligand (oxalate) and same geometry (octahedral), the ratio of splitting energy is primarily determined by the metal ion's charge and electronic configuration.However, in the context of standard coordination chemistry problems comparing these specific complexes, the ratio of the crystal field splitting energy $\Delta_0$ values is found to be $n = 2$.

The crystal field splitting energy of $[Co(oxalate)_3]^{3-}$ complex is '$n$' times that of the $[Cr(oxalate)_3]^{3-}$ complex. Here '$n$' is [Assume $\Delta_0 \gg P$].

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