The crystal field stabilization energy (CFSE) | vedclass

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Question

(D) In $[CoF_{3}(H_{2}O)_{3}]$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $3d^{6}$.Given $\Delta_{0} < P$,the c

Vedclass · Accepted Answer

$-0.4 \Delta_{0}$

Vedclass · Answer

(D) In $[CoF_{3}(H_{2}O)_{3}]$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $3d^{6}$.Given $\Delta_{0} The distribution of $6$ electrons in $d$-orbitals is $t_{2g}^{4} e_{g}^{2}$.$CFSE = [n(t_{2g}) 	imes (-0.4) + n(e_{g}) 	imes (0.6)] \Delta_{0}$$CFSE = [4 	imes (-0.4) + 2 	imes (0.6)] \Delta_{0}$$CFSE = [-1.6 + 1.2] \Delta_{0} = -0.4 \Delta_{0}$

The crystal field stabilization energy $(CFSE)$ of $[CoF_{3}(H_{2}O)_{3}]$ $(\Delta_{0} < P)$ is $:-$

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