The current through an ideal PN- junction dio | vedclass

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(A) In the given circuit,the $P$-terminal of the diode is connected to the positive terminal of a $1 	ext{ V}$ battery,and the $N$-terminal is connec

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$0$

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(A) In the given circuit,the $P$-terminal of the diode is connected to the positive terminal of a $1 	ext{ V}$ battery,and the $N$-terminal is connected to the positive terminal of a $2 	ext{ V}$ battery through a $100 \ \Omega$ resistor.Thus,the potential at the $P$-side is $V_P = 1 	ext{ V}$ and the potential at the $N$-side is $V_N = 2 	ext{ V}$.Since $V_P An ideal diode in reverse bias acts as an open circuit and does not conduct any current.Therefore,the current through the diode is $0 	ext{ mA}$.

The current through an ideal $PN-$ junction diode shown in the following circuit diagram will be.......$mA$.

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