The current through the ammeter (neglecting i | vedclass

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(B) Since both diodes are connected in forward bias, the given circuit diagram can be simplified by replacing the diodes with short circuits (assuming

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$1$ $A$

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(B) Since both diodes are connected in forward bias, the given circuit diagram can be simplified by replacing the diodes with short circuits (assuming ideal diodes).The two $10 \Omega$ resistors are connected in parallel.The equivalent resistance of the circuit is:$R_{eq} = \frac{10 	imes 10}{10 + 10} = 5 \Omega$Therefore, the current through the ammeter is:$I = \frac{V}{R_{eq}} = \frac{5 	ext{ V}}{5 \Omega} = 1 	ext{ A}$

The current through the ammeter (neglecting internal resistance) in the following circuit is

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