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(B) Given:Height $(h) = 14\, cm$Curved surface area $(CSA) = 88\, cm^2$Let the radius of the base be $r$ and the diameter be $d = 2r$.The formula for

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(B) Given:Height $(h) = 14\, cm$Curved surface area $(CSA) = 88\, cm^2$Let the radius of the base be $r$ and the diameter be $d = 2r$.The formula for the curved surface area of a cylinder is $CSA = 2\pi rh$.Since $d = 2r$,we can write $CSA = \pi dh$.Substituting the given values:$88 = \frac{22}{7} 	imes d 	imes 14$$88 = 22 	imes d 	imes 2$$88 = 44 	imes d$$d = \frac{88}{44} = 2\, cm$.Thus,the diameter of the base of the cylinder is $2\, cm$.

The curved surface area of a right circular cylinder of height $14\, cm$ is $88\, cm^2$. Find the diameter of the base of the cylinder.
Assume $\pi = \frac{22}{7}$ unless stated otherwise. (in $, cm$)

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The curved surface area of a right circular cylinder of height $14\, cm$ is $88\, cm^2$. Find the diameter of the base of the cylinder.Assume $\pi = \frac{22}{7}$ unless stated otherwise. (in $, cm$)