The de-Broglie wavelength of a tennis ball of mass $60 \ g$ moving with a velocity of $10 \ ms^{-1}$ is approximately . . . . . . (Planck's constant $h = 6.63 \times 10^{-34} \ J \cdot s$).
- A$1.1 \times 10^{-31} \ m$
- B$1.1 \times 10^{-33} \ m$
- C$1.1 \times 10^{-34} \ m$
- D$1.1 \times 10^{-32} \ m$
Explore More
Similar Questions
The de Broglie wavelength of a tennis ball of $60 \ g$ moving with a velocity of $10 \ m/s$ is approximately
Medium
View SolutionIn a hydrogen atom,the de Broglie wavelength of an electron in the second Bohr orbit is: [Given that Bohr radius,$a_0 = 52.9 \; pm$]
The de Broglie wavelengths of two fast moving particles $X$ and $Y$ are $1 \ nm$ and $3 \ nm$ respectively. The mass of $X$ is nine times the mass of $Y$. The ratio of kinetic energies of $X$ and $Y$ is:
Calculate the velocity of an electron having a de Broglie wavelength of $58 \ nm$ and mass $9.1 \times 10^{-31} \ kg$. Given: $h = 6.63 \times 10^{-34} \ Js$.
Write about the dual behaviour of matter.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo