The decreasing order of hydride affinity for the following carbocations is:
$A: CH_2=CH-C^+(CH_3)_2$
$B: (C_6H_5)_3C^+$
$C: (CH_3)_3C^+$
$D: (Cyclopropyl)_3C^+$
Choose the correct answer from the options given below:

Arrange the following free radicals in the correct order of their stability:
$(i)$ $CH_2=\dot{C}H$
$(ii)$ $\dot{C}H_3$
$(iii)$ $CH_3-\dot{C}H-CH_3$
$(iv)$ $(CH_3)_3\dot{C}$

Classify the following species into carbocation,free radical,and carbanion:
$CH_3^{\bullet}, CH_3^{+}, \bar{C}H_3, (CH_3)_3C^{\bullet}, (CH_3)_3C^{+}, (CH_3)_2CH^{+}, (CH_3)_3\bar{C}:, (CH_3)_3\ddot{C}H, C_6H_5CH_2^{\bullet}, CH_3\ddot{C}H_2, C_6H_5CH_2^{+}, CH_2=CHCH_2^{\bullet}, CH_2=CHCH_2^{+}$

Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:

The lower stability of ethyl anion compared to methyl anion and the higher stability of ethyl radical compared to methyl radical,respectively,are due to

What type of reaction is oxidative rancidity?