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(A) The reactivity of alcohols with halo acids depends on the stability of the carbocation intermediate formed during the reaction.The order of stabil

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$(IV) > (III) > (II) > (I)$

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(A) The reactivity of alcohols with halo acids depends on the stability of the carbocation intermediate formed during the reaction.The order of stability of carbocations is $3^\circ > 2^\circ > 1^\circ > 	ext{methyl}$.Therefore,the order of reactivity of alcohols is $3^\circ > 2^\circ > 1^\circ > 	ext{methyl}$.$(I)$ $CH_3OH$ is a methyl alcohol.$(II)$ $CH_3CH_2OH$ is a $1^\circ$ alcohol.$(III)$ $(CH_3)_2CHOH$ is a $2^\circ$ alcohol.$(IV)$ $(CH_3)_3COH$ is a $3^\circ$ alcohol.Thus,the decreasing order of reactivity is $(IV) > (III) > (II) > (I)$.

The decreasing order of reactivity of the following alcohols with halo acid is:
$(I)$ $CH_3OH$
$(II)$ $CH_3CH_2OH$
$(III)$ $(CH_3)_2CHOH$
$(IV)$ $(CH_3)_3COH$

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The decreasing order of reactivity of the following alcohols with halo acid is:$(I)$ $CH_3OH$$(II)$ $CH_3CH_2OH$$(III)$ $(CH_3)_2CHOH$$(IV)$ $(CH_3)_3COH$