The decreasing order of the number of ionisab | vedclass

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(C) The number of ionisable hydrogen atoms in an oxoacid of phosphorus is equal to the number of $P-OH$ bonds present in the molecule.$1$. $H_3PO_4$ (

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$IV > I > II > III$

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(C) The number of ionisable hydrogen atoms in an oxoacid of phosphorus is equal to the number of $P-OH$ bonds present in the molecule.$1$. $H_3PO_4$ (Orthophosphoric acid): Contains $3$ $P-OH$ bonds, so it has $3$ ionisable hydrogen atoms.$2$. $H_3PO_3$ (Phosphorous acid): Contains $2$ $P-OH$ bonds, so it has $2$ ionisable hydrogen atoms.$3$. $H_3PO_2$ (Hypophosphorous acid): Contains $1$ $P-OH$ bond, so it has $1$ ionisable hydrogen atom.$4$. $H_4P_2O_6$ (Hypophosphoric acid): Contains $4$ $P-OH$ bonds, so it has $4$ ionisable hydrogen atoms.Comparing the number of ionisable hydrogen atoms:$IV (4) > I (3) > II (2) > III (1)$Therefore, the decreasing order is $IV > I > II > III$.

The decreasing order of the number of ionisable hydrogen atoms in the following molecules is:
$I$. $H_3PO_4$
$II$. $H_3PO_3$
$III$. $H_3PO_2$
$IV$. $H_4P_2O_6$

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The decreasing order of the number of ionisable hydrogen atoms in the following molecules is:$I$. $H_3PO_4$$II$. $H_3PO_3$$III$. $H_3PO_2$$IV$. $H_4P_2O_6$