The degree of the differential equation left[ | vedclass

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(A) The given differential equation is $\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{2}=\frac{d^{2}y}{dx^{2}}$.To find the degree,we first identify

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$1$

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(A) The given differential equation is $\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{2}=\frac{d^{2}y}{dx^{2}}$.To find the degree,we first identify the highest order derivative present in the equation.The highest order derivative is $\frac{d^{2}y}{dx^{2}}$,which has an order of $2$.The degree of a differential equation is the power of the highest order derivative when the equation is expressed as a polynomial in terms of derivatives.In the given equation,the highest order derivative $\frac{d^{2}y}{dx^{2}}$ has an exponent of $1$.Therefore,the degree of the differential equation is $1$.

The degree of the differential equation $\left[1+\left(\frac{dy}{dx}\right)^{2}\right]^{2}=\frac{d^{2}y}{dx^{2}}$ is

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