The density of beta-Fe is 7.6 g cm^{-3}. It | vedclass

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(A) The density formula for a cubic crystal is $ho = \frac{Z 	imes M}{N_A 	imes a^3}$.Given values are $ho = 7.6 \ g \ cm^{-3}$,$M = 56 \ g \ mo

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$2$

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(A) The density formula for a cubic crystal is $ho = \frac{Z 	imes M}{N_A 	imes a^3}$.Given values are $ho = 7.6 \ g \ cm^{-3}$,$M = 56 \ g \ mol^{-1}$,$N_A = 6.022 	imes 10^{23} \ mol^{-1}$,and $a = 290 \ pm = 290 	imes 10^{-10} \ cm$.Rearranging the formula for $Z$: $Z = \frac{ho 	imes N_A 	imes a^3}{M}$.Substituting the values: $Z = \frac{7.6 	imes 6.022 	imes 10^{23} 	imes (290 	imes 10^{-10})^3}{56}$.$Z = \frac{7.6 	imes 6.022 	imes 10^{23} 	imes 24389 	imes 10^{-30}}{56}$.$Z = \frac{1115780.8 	imes 10^{-7}}{56} \approx \frac{0.111578}{0.056} \approx 1.99$.Thus,the value of $Z$ is approximately $2$.

The density of $\beta-Fe$ is $7.6 \ g \ cm^{-3}$. It crystallizes in a cubic lattice with $a = 290 \ pm$. What is the value of $Z$? $(Fe = 56 \ g \ mol^{-1}; N_{A} = 6.022 \times 10^{23} \ mol^{-1})$

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