The depth $d$ at which the value of acceleration due to gravity becomes $\frac{1}{n}$ times the value at the earth's surface is $(R = \text{radius of the earth})$
- A$d=R\left(\frac{n}{n-1}\right)$
- B$d=R\left(\frac{n-1}{2n}\right)$
- C$d=R\left(\frac{n-1}{n}\right)$
- D$d=R^2\left(\frac{n-1}{n}\right)$
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