The treatment of Ph_2C(OH)CH_2NH_2 with NaNO_ | vedclass

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(B) The reaction of $Ph_2C(OH)CH_2NH_2$ with $NaNO_2 - HCl$ involves the diazotization of the primary amine to form an unstable diazonium salt. This i

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$Ph-C(=O)-CH_2-Ph$

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(B) The reaction of $Ph_2C(OH)CH_2NH_2$ with $NaNO_2 - HCl$ involves the diazotization of the primary amine to form an unstable diazonium salt. This is followed by a $1,2-Ph$ shift (Tiffeneau-Demjanov rearrangement type) to form a carbocation,which then loses a proton to form the ketone $Ph-C(=O)-CH_2-Ph$. This product $(P)$ is $1,2-diphenylethanone$ (deoxybenzoin). Upon oxidation,$Ph-C(=O)-CH_2-Ph$ undergoes cleavage to yield benzoic acid as the primary product.

The treatment of $Ph_2C(OH)CH_2NH_2$ with $NaNO_2 - HCl$ gives a product $(P)$ which on oxidation gives benzoic acid only. Identify the product $(P)$.

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