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(A) The correct answer is $A$.The expression of genetic material occurs normally through the production of proteins. This involves two consecutive ste

Vedclass · Accepted Answer

$A$ - Transcription,$B$ - Translation,$C$ - Francis Crick

Vedclass · Answer

(A) The correct answer is $A$.The expression of genetic material occurs normally through the production of proteins. This involves two consecutive steps: transcription and translation.$1$. Transcription $(A)$: The $DNA$ codes for the production of messenger $RNA$ $(mRNA)$.$2$. Translation $(B)$: The $mRNA$ carries coded information to ribosomes,which read this information and use it for protein synthesis.$3$. Central Dogma $(C)$: $F.H.C.$ Crick described this unidirectional flow of information in $1958$ as the 'central dogma of molecular biology'.

List-$I$	List-$II$
$A$. Monocistronic gene	$I$. Coding sequence
$B$. Polycistronic gene	$II$. Intervening sequence
$C$. Exons	$III$. Mostly prokaryotes
$D$. Introns	$IV$. Mostly eukaryotes

The diagram shows an important concept in the genetic implication of $DNA$. Fill in the blanks $A$ to $C$.

Similar Questions

The one-gene-one-enzyme relationship was first established in.....

Assertion : Histones are basic proteins of major importance in packaging of eukaryotic $DNA$. $DNA$ and histones comprise chromatin forming the bulk of eukaryotic chromosome.
Reason : Histones are of five major types $H_1, H_2A, H_2B, H_3$ and $H_4$.

Which of the following is not a correct statement?

The life span of $mRNA$ in $E. coli$ is:

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A$. Monocistronic gene $I$. Coding sequence

$B$. Polycistronic gene $II$. Intervening sequence

$C$. Exons $III$. Mostly prokaryotes

$D$. Introns $IV$. Mostly eukaryotes

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