The diameter of the objective of a telescope is $1 \ m$. Its resolving limit for light of wavelength $4538 \ \text{Å}$ will be:
- A$5.54 \times 10^{-7} \ \text{rad}$
- B$2.54 \times 10^{-4} \ \text{rad}$
- C$6.54 \times 10^{-7} \ \text{rad}$
- DNone of these
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Wavelengths of light used in an optical instrument are $\lambda_1 = 4000 \; \mathring{A}$ and $\lambda_2 = 5000 \; \mathring{A}$. The ratio of their respective resolving powers (corresponding to $\lambda_1$ and $\lambda_2$) is:
Two points separated by $0.05 \, mm$ can just be inspected in a microscope when light of wavelength $6000 \, \mathring{A}$ is used. If light of wavelength $3000 \, \mathring{A}$ is used,then the limit of resolution becomes ........... $mm$.
Easy
View SolutionWith the help of a telescope that has an objective of diameter $200 \,cm$, it is proved that light of wavelengths of the order of $6400 \text{ Å}$ coming from a star can be easily resolved. Then, the limit of resolution is
The resolving power of a telescope depends on
Easy
View Solution$A$ microscope has an objective of aperture $8 \text{ mm}$ and focal length of $5 \text{ cm}$. The minimum separation between two objects to be just resolved by the microscope is (wavelength of light used $= 5500 \text{ Å}$) (in $\mu\text{m}$)
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