The diameter of the objective of the telescop | vedclass

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(D) The resolving power of a telescope is given by the formula: $RP = \frac{D}{1.22 \lambda}$.Here,the diameter of the objective $D = 0.1 \ m$ and the

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$1.36 	imes 10^{5} \ rad$

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(D) The resolving power of a telescope is given by the formula: $RP = \frac{D}{1.22 \lambda}$.Here,the diameter of the objective $D = 0.1 \ m$ and the wavelength $\lambda = 6000 \ \mathring{A} = 6000 	imes 10^{-10} \ m = 6 	imes 10^{-7} \ m$.Substituting these values into the formula:$RP = \frac{0.1}{1.22 	imes 6 	imes 10^{-7}}$$RP = \frac{0.1}{7.32 	imes 10^{-7}}$$RP = \frac{10^{-1}}{7.32 	imes 10^{-7}} = \frac{1}{7.32} 	imes 10^{6} \approx 0.1366 	imes 10^{6} \approx 1.36 	imes 10^{5} \ rad^{-1}$.Note: Resolving power is a dimensionless quantity (or expressed in $rad^{-1}$),and the options provided represent the magnitude of this value.

The diameter of the objective of the telescope is $0.1 \ m$ and the wavelength of light is $6000 \ \mathring{A}$. Its resolving power would be approximately:

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