The difference between spin-only magnetic mom | vedclass

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Question

(C) For $[Co(H_2O)_6]Cl_2$:$Co^{2+}$ has a $3d^7$ configuration. In an octahedral field,the electrons are arranged as $t_{2g}^5 e_g^2$,resulting in $3

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$0$

Vedclass · Answer

(C) For $[Co(H_2O)_6]Cl_2$:$Co^{2+}$ has a $3d^7$ configuration. In an octahedral field,the electrons are arranged as $t_{2g}^5 e_g^2$,resulting in $3$ unpaired electrons.The spin-only magnetic moment $\mu = \sqrt{n(n+2)} \ BM = \sqrt{3(3+2)} = \sqrt{15} \ BM$.For $[Cr(H_2O)_6]Cl_3$:$Cr^{3+}$ has a $3d^3$ configuration. The electrons are arranged as $t_{2g}^3 e_g^0$,resulting in $3$ unpaired electrons.The spin-only magnetic moment $\mu = \sqrt{n(n+2)} \ BM = \sqrt{3(3+2)} = \sqrt{15} \ BM$.Difference in spin-only magnetic moment $= \sqrt{15} - \sqrt{15} = 0$.

The difference between spin-only magnetic moment values of $[Co(H_2O)_6]Cl_2$ and $[Cr(H_2O)_6]Cl_3$ is $....$

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