The difference between the orbital angular mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The orbital angular momentum is given by the formula: $	ext{Orbital angular momentum} = \sqrt{\ell(\ell+1)} \frac{h}{2 \pi}$.For a $4f$ orbital,

Vedclass · Accepted Answer

$2 \sqrt{3} 	imes \frac{h}{2 \pi}$

Vedclass · Answer

(A) The orbital angular momentum is given by the formula: $	ext{Orbital angular momentum} = \sqrt{\ell(\ell+1)} \frac{h}{2 \pi}$.For a $4f$ orbital, the azimuthal quantum number $\ell = 3$. Therefore, the orbital angular momentum is $\sqrt{3(3+1)} \frac{h}{2 \pi} = \sqrt{12} \frac{h}{2 \pi} = 2 \sqrt{3} \frac{h}{2 \pi}$.For a $4s$ orbital, the azimuthal quantum number $\ell = 0$. Therefore, the orbital angular momentum is $\sqrt{0(0+1)} \frac{h}{2 \pi} = 0$.The difference between the two is $2 \sqrt{3} \frac{h}{2 \pi} - 0 = 2 \sqrt{3} \frac{h}{2 \pi}$.

The difference between the orbital angular momentum of an electron in a $4f$ orbital and another electron in a $4s$ orbital is

Similar Questions

The number of unpaired electrons in the $Fe^{2+}$ ion is

Find the number of electron pairs in $P$ atom with $l = 1$ and $m = 0$.

The number of unpaired electrons in $1s^2 2s^2 2p^3$ is:

What is the atomic number of the element with $M^{2+}$ ion having electronic configuration $[Ar] 3d^8$?

The electronic configuration $1s^2, 2s^2 2p^5, 3s^1$ represents:

Vedclass Test Series

Exam Paper Generator

Online Exam Module