The difference of any two sides of a triangle is $\ldots \ldots \ldots$ than the third side.

In $\Delta ABC$ and $\Delta PQR$,if $\frac{AB}{PQ} = \frac{BC}{RQ} = \frac{AC}{PR} = 1$,then $\Delta ABC \cong \Delta \ldots \ldots \ldots$

"If two angles and a side of one triangle are equal to two angles and a side of another triangle,then the two triangles must be congruent." Is the statement true? Why?

$S$ is any point in the interior of $\triangle PQR$. Show that $SQ + SR < PQ + PR$.

Write the measures of the sides of $\Delta PQR$ in ascending order,given that $\angle P = 93^{\circ}$ and $\angle R = 55^{\circ}$.

If $\Delta ABC \cong \Delta YZX,$ then in $\Delta XYZ,$ which side is equal to side $AB$?