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(B) The magnetic force on a current-carrying conductor is given by $F = BIl \sin 	heta$. Thus,the magnetic field $B = F / (Il)$.The dimensions of for

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magnetic permeability

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(B) The magnetic force on a current-carrying conductor is given by $F = BIl \sin 	heta$. Thus,the magnetic field $B = F / (Il)$.The dimensions of force $F$ are $[MLT^{-2}]$.The dimensions of current $I$ are $[A]$.The dimensions of length $l$ are $[L]$.Therefore,the dimensions of $B$ are $[MLT^{-2}] / ([A][L]) = [MT^{-2}A^{-1}]$.The magnetic permeability $\mu$ is related to $B$ and $H$ by $B = \mu H$,where $H$ has dimensions $[IL^{-1}] = [AL^{-1}]$.Thus,$\mu = B / H = [MT^{-2}A^{-1}] / [AL^{-1}] = [MLT^{-2}A^{-2}]$.Hence,the dimensions $[MLT^{-2}A^{-2}]$ correspond to magnetic permeability.

The dimensions $[MLT^{-2}A^{-2}]$ belong to:

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