The directrix of the parabola ${x^2 - 4x - 8y + 12 = 0}$ is

  • A
    $x = 1$
  • B
    $y = 0$
  • C
    $x = -1$
  • D
    $y = -1$

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If the lines $2x + 3y + 12 = 0$ and $x - y + k = 0$ are conjugate with respect to the parabola $y^2 = 8x$,then $k$ is equal to

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$A$ line $L: y=mx+3$ meets the $y$-axis at $E(0,3)$ and the arc of the parabola $y^2=16x, 0 \leq y \leq 6$ at the point $F(x_0, y_0)$. The tangent to the parabola at $F(x_0, y_0)$ intersects the $y$-axis at $G(0, y_1)$. The slope $m$ of the line $L$ is chosen such that the area of the triangle $EFG$ has a local maximum.
Match List $I$ with List $II$ and select the correct answer using the code given below the lists:
List $I$ List $II$
$P. \quad m=$ $1. \quad 1/2$
$Q. \quad \text{Maximum area of } \triangle EFG \text{ is}$ $2. \quad 4$
$R. \quad y_0=$ $3. \quad 2$
$S. \quad y_1=$ $4. \quad 1$

Codes: $P \quad Q \quad R \quad S$

The locus of a point which divides the line segment joining the focus and any point on the parabola $y^2 = 12x$ in the ratio $m:n$ $(m+n \neq 0)$ is a parabola. Then the length of the latus rectum of that parabola is

The angle of intersection between the curves $x^2 = 4(y + 1)$ and $x^2 = -4(y + 1)$ is

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