The displacement of a particle,moving in a st | vedclass

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Question

(B) The displacement of the particle is given by the equation $s = 2t^2 + 2t + 4$.To find the velocity $v$,we differentiate the displacement $s$ with

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The displacement of the particle is given by the equation $s = 2t^2 + 2t + 4$.To find the velocity $v$,we differentiate the displacement $s$ with respect to time $t$:$v = \frac{ds}{dt} = \frac{d}{dt}(2t^2 + 2t + 4) = 4t + 2$.To find the acceleration $a$,we differentiate the velocity $v$ with respect to time $t$:$a = \frac{dv}{dt} = \frac{d}{dt}(4t + 2) = 4$.Thus,the acceleration of the particle is $4 \ m/s^2$.

The displacement of a particle,moving in a straight line,is given by $s = 2t^2 + 2t + 4$,where $s$ is in metres and $t$ is in seconds. The acceleration of the particle is ........ $m/s^2$.

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