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(B) The displacement of the particle is given by $s = 6t^2 - t^3$.Velocity $v$ is the rate of change of displacement with respect to time,given by $v

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$4$

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(B) The displacement of the particle is given by $s = 6t^2 - t^3$.Velocity $v$ is the rate of change of displacement with respect to time,given by $v = \frac{ds}{dt}$.$v = \frac{d}{dt}(6t^2 - t^3) = 12t - 3t^2$.To find the time when the velocity is zero,we set $v = 0$:$12t - 3t^2 = 0$.$3t(4 - t) = 0$.This gives $t = 0 \ s$ and $t = 4 \ s$.The particle starts from rest at $t = 0 \ s$,so it will attain zero velocity again at $t = 4 \ s$.

The displacement of a particle starting from rest (at $t = 0$) is given by $s = 6t^2 - t^3$. The time in seconds at which the particle will attain zero velocity again,is ..... $s$.

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