Medium
The displacement-time graphs of two moving particles make angles of $30^{\circ}$ and $45^{\circ}$ with the time axis. The ratio of their velocities is
- A$\sqrt{3}: 2$
- B$1: 1$
- C$1: 2$
- D$1: \sqrt{3}$
Explore More
Similar Questions
The acceleration versus velocity graph of a particle moving in a straight line,starting from rest,is as shown in the figure. The corresponding velocity-time graph would be:
Medium
View SolutionThe velocity $v$ of a particle is given by the equation $v = 6t^2 - 6t^3$,where $v$ is in $m/s$ and $t$ is time in $s$. Then:
Medium
View Solution$y = (P t^2 - Q t^3) \ m$ is the vertical displacement of a ball which is moving in a vertical plane. Then the maximum height that the ball can reach is,
DifficultAP EAMCET 2022
View SolutionRefer to the graph in figure. Match the following:
Graph Characteristics $(A)$ $(i)$ has $v > 0$ and $a < 0$ throughout $(B)$ $(ii)$ has $x > 0$ throughout and has a point with $v = 0$ and a point with $a = 0$ $(C)$ $(iii)$ has a point with zero displacement for $t > 0$ $(D)$ $(iv)$ has $v < 0$ and $a > 0$
| Graph | Characteristics |
| $(A)$ | $(i)$ has $v > 0$ and $a < 0$ throughout |
| $(B)$ | $(ii)$ has $x > 0$ throughout and has a point with $v = 0$ and a point with $a = 0$ |
| $(C)$ | $(iii)$ has a point with zero displacement for $t > 0$ |
| $(D)$ | $(iv)$ has $v < 0$ and $a > 0$ |
Medium
View SolutionThe velocity-time graph for a particle moving along the $x$-axis is shown in the figure. The corresponding displacement-time graph is correctly shown by
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo