The distance between A(cos theta, 0) and B(0, | vedclass

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(B) The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given p

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$1$

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(B) The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(\cos 	heta, 0)$ and $B(0, \sin 	heta)$.Substituting the coordinates into the formula:$d = \sqrt{(0 - \cos 	heta)^2 + (\sin 	heta - 0)^2}$$d = \sqrt{(-\cos 	heta)^2 + (\sin 	heta)^2}$$d = \sqrt{\cos^2 	heta + \sin^2 	heta}$Using the trigonometric identity $\sin^2 	heta + \cos^2 	heta = 1$,we get:$d = \sqrt{1} = 1$.

The distance between $A(\cos \theta, 0)$ and $B(0, \sin \theta)$ is ...........

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