The distance between the carbon atom and the | vedclass

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(C) Given:Mass of carbon atom,$m_C = 12 amu$Mass of oxygen atom,$m_O = 16 amu$Distance between them,$r = 1.1 Å$Let $x$ be the distance of the centre o

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$0.63 Å$ from the carbon atom

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(C) Given:Mass of carbon atom,$m_C = 12 amu$Mass of oxygen atom,$m_O = 16 amu$Distance between them,$r = 1.1 Å$Let $x$ be the distance of the centre of mass from the carbon atom.Using the formula for the centre of mass of a two-particle system,the distance $x$ from the carbon atom is given by:$x = \frac{m_O \cdot r}{m_C + m_O}$Substituting the given values:$x = \frac{16 \cdot 1.1}{12 + 16}$$x = \frac{17.6}{28}$$x = 0.62857 Å \approx 0.63 Å$Therefore,the centre of mass is located at $0.63 Å$ from the carbon atom.

The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is $1.1 Å$. Given,mass of carbon atom is $12 amu$ and mass of oxygen atom is $16 amu$. Calculate the position of the centre of mass of the carbon monoxide molecule.

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