(C) Let the carbon atom be at the origin $(0, 0)$ and the oxygen atom be placed at $(1.1, 0)$ on the $x$-axis.Given: $m_1 = 12 \ a.m.u.$ (carbon),$m_2

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$0.63 \ \mathring{A}$ from the carbon atom

(C) Let the carbon atom be at the origin $(0, 0)$ and the oxygen atom be placed at $(1.1, 0)$ on the $x$-axis.Given: $m_1 = 12 \ a.m.u.$ (carbon),$m_2 = 16 \ a.m.u.$ (oxygen).Position vectors are $\vec{r}_1 = 0\hat{i}$ and $\vec{r}_2 = 1.1\hat{i}$.The center of mass $R_{cm}$ is given by:$R_{cm} = \frac{m_1 r_1 + m_2 r_2}{m_1 + m_2}$$R_{cm} = \frac{12(0) + 16(1.1)}{12 + 16}$$R_{cm} = \frac{17.6}{28} \ \mathring{A}$$R_{cm} \approx 0.63 \ \mathring{A}$ from the carbon atom.

Class 11 Physics System of Particles and Rotational Motion Centre of mass (Point Mass)

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The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is $1.1 \ \mathring{A}$. Given,mass of carbon atom is $12 \ a.m.u.$ and mass of oxygen atom is $16 \ a.m.u.$,calculate the position of the center of mass of the carbon monoxide molecule.

A
$6.3 \ \mathring{A}$ from the carbon atom
B
$1 \ \mathring{A}$ from the oxygen atom
C
$0.63 \ \mathring{A}$ from the carbon atom
D
$0.12 \ \mathring{A}$ from the oxygen atom

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System of Particles and Rotational Motion

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Centre of mass (Point Mass)

Four particles of masses $m, 2m, 3m$ and $4m$ are arranged at the corners of a parallelogram with each side equal to $a$ and one of the angles between two adjacent sides is $60^o$. The parallelogram lies in the $x-y$ plane with mass $m$ at the origin and $4m$ on the $x$-axis. The centre of mass of the arrangement will be located at

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$A$ $T$-shaped object with dimensions shown in the figure is lying on a smooth floor. $A$ force $\vec{F}$ is applied at point $P$ parallel to $AB$,such that the object has only translational motion without rotation. Find the location of $P$ with respect to $C$.

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In carbon monoxide molecules,the carbon and the oxygen atoms are separated by a distance of $1.2 \,\mathring{A}$. The distance of the centre of mass from the carbon atom is ........ $\mathring{A}$.

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When two masses $m$ and $M$ $(M > m)$ are connected,where will the center of mass be located?

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Where is the centre of mass of two isolated particles of equal mass located?

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The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is $1.1 \ \mathring{A}$. Given,mass of carbon atom is $12 \ a.m.u.$ and mass of oxygen atom is $16 \ a.m.u.$,calculate the position of the center of mass of the carbon monoxide molecule.

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$A$ $T$-shaped object with dimensions shown in the figure is lying on a smooth floor. $A$ force $\vec{F}$ is applied at point $P$ parallel to $AB$,such that the object has only translational motion without rotation. Find the location of $P$ with respect to $C$.

In carbon monoxide molecules,the carbon and the oxygen atoms are separated by a distance of $1.2 \,\mathring{A}$. The distance of the centre of mass from the carbon atom is ........ $\mathring{A}$.

When two masses $m$ and $M$ $(M > m)$ are connected,where will the center of mass be located?

Where is the centre of mass of two isolated particles of equal mass located?

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