The distance between the line $\bar{r} = 3\hat{i} - 2\hat{j} + \hat{k} + \lambda(\hat{i} - 2\hat{j})$ and the plane $\bar{r} \cdot (2\hat{i} + \hat{j} + \hat{k}) = 4$ is

  • A
    $\frac{1}{\sqrt{6}}$ units
  • B
    $\frac{3}{\sqrt{6}}$ units
  • C
    $\frac{2}{\sqrt{6}}$ units
  • D
    $\frac{5}{\sqrt{6}}$ units

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