The distance of the point (b cos theta, b sin | vedclass

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(B) The distance $d$ of a point $(x, y)$ from the origin $(0, 0)$ is given by the formula $d = \sqrt{x^2 + y^2}$.Substituting the given coordinates $(

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$b$

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(B) The distance $d$ of a point $(x, y)$ from the origin $(0, 0)$ is given by the formula $d = \sqrt{x^2 + y^2}$.Substituting the given coordinates $(b \cos 	heta, b \sin 	heta)$:$d = \sqrt{(b \cos 	heta)^2 + (b \sin 	heta)^2}$$d = \sqrt{b^2 \cos^2 	heta + b^2 \sin^2 	heta}$$d = \sqrt{b^2(\cos^2 	heta + \sin^2 	heta)}$Since $\cos^2 	heta + \sin^2 	heta = 1$,we get:$d = \sqrt{b^2(1)} = b$.

The distance of the point $(b \cos \theta, b \sin \theta)$ from the origin is

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