The driver of a three-wheeler moving with a s | vedclass

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(D) Initial speed of the three-wheeler,$u = 36\; km/h = 36 	imes \frac{5}{18} = 10\; m/s$.Final speed of the three-wheeler,$v = 0\; m/s$.Time taken t

Vedclass · Accepted Answer

$1162.5$

Vedclass · Answer

(D) Initial speed of the three-wheeler,$u = 36\; km/h = 36 	imes \frac{5}{18} = 10\; m/s$.Final speed of the three-wheeler,$v = 0\; m/s$.Time taken to stop,$t = 4.0\; s$.Total mass of the system,$M = 400\; kg + 65\; kg = 465\; kg$.Using the first equation of motion,$v = u + at$,the acceleration $a$ is:$a = \frac{v - u}{t} = \frac{0 - 10}{4} = -2.5\; m/s^2$.The negative sign indicates retardation.Using Newton's second law of motion,the retarding force $F$ is:$F = M 	imes |a| = 465 	imes 2.5 = 1162.5\; N$.

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